pemfaktoran dari 2x² - 5x + 3 adalah....

Mapel : Matematika
Materi : Faktorisasi Persamaan Kuadrat

[tex]a=2,\ b=-5,\ c=3\\ \\x_{1}= \frac{-b+\sqrt{b^2-4ac}}{2a}\\ \\x_{1}= \frac{-(-5)+\sqrt{(-5)^2-4(2)(3)}}{2(2)}\\ \\x_{1}= \frac{5+\sqrt{25-24}}{4}\\ \\x_{1}= \frac{5+\sqrt{1}}{4}\\ \\x_{1}=\frac{5+1}{4}\\ \\x_{1}=\frac{6}{4}\\ \\x_{1}=\frac{3}{2}......\ x- \frac{3}{2} =0....kedua\ ruas\ dikalikan\ 2 \to (2x-3)[/tex]

[tex]x_{2}= \frac{-(-5)-\sqrt{(-5)^2-4(2)(3)}}{2(2)}\\ \\x_{2}= \frac{5-\sqrt{25-24}}{4}\\ \\x_{2}= \frac{5-\sqrt{1}}{4}\\ \\x_{2}=\frac{5-1}{4}\\ \\x_{2}=\frac{4}{4}\\ \\x_{2}=1......\ x- 1 =0.... \to (x-1)[/tex]

Jadi hasil pemfaktorannya adalah 

[tex]2x^2-5x+3=0 \\ \\ (2x-3)(x-1)=0[/tex]

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