Nilai dari 3log18 + 3log6 - 3log12 adalah...

semoga jawabanya membantu:)

[tex]^{3} log18 + ^{3} log6 - ^{3}log12 \\ = ^{3}log(18 \times 6 \div 12) \\ = ^{3}log9 \\ = ^{3}log {3}^{2} \\ = 2 \times ^{3}log3 \\ = 2(1) \\ = 2[/tex]