g(x) = -x +3 fog (x) = 4x^2 - 26x + 32 f(1)=

Materi : Fungsi Komposisi

(fog) (x) = 4x² -26x + 32
f(g(x)) = 4x² -26x + 32 -----> masukkan g(x)
f(-x+3) = 4x² -26x + 32

-x+3 = 1
-x = -2
x=2

f(-2+3) = 4(2)² -26 (2) +32
f(1) = 16 -52 +32 = -4

semoga membantu