Hitunglah PH da 12,5 gr HCl dilarutkan dalam 2 liter air jika diketahui Ar H = 1, Cl = 35,5?

mol = massa/Mr = 12,5/36,5 = 0,34
M = mol/V = 0,34/2 = 0,17
H+ HCl (asam kuat) = n x M = 1 x 0,17 = 1,7x10^-1
pH = - log H+
pH = 1 - log 1,7