diketahui g(x) = 2x-1 dan f o g = 4x^2+10x+11. Rumus fungsi untuk f(x) adalah

[tex] {g}^{ - 1} x = \frac{x + 1}{2} \\ \\ gof = 4 {x}^{2} + 10x + 11 \\ = 4( \frac{(x + 1)}{2})^{2} + 10( \frac{x + 1}{2} ) + 11 \\ = x^{2} + 2x + 1 + 5x + 5 + 11 \\ = {x}^{2} + 7x + 17[/tex]

fog(x) = 4x²+10x+11
f(g(x)) = 4x²+10x+11
f(2x-1) = 4x²+10x+11
           = 4(2x-1)²+10(2x-1)+11
           = 4(4x²-2x-2x+1)+10(2x-1)+11
           = 4(4x²-4x+4)+10(2x-1)+11
           = 16x²-16x+4+20x-10+11
           = 16x²+4x+5