tolong bantu yaaa pake caranya please

[tex] {3}^{2x - 3} = ( \frac{1}{27} ) ^{x + 3} \\ {3}^{2x - 3} = ( \frac{1}{ {3}^{3} } ) ^{x + 3} \\ {3}^{2x - 3} = ( {3}^{ - 3} ) ^{x + 3} \\ {3}^{2x - 3} = {3}^{ - 3x - 9} \\ 2x - 3 = - 3x - 9 \\ 5x = - 6 \\ x = \frac{ - 6}{5} [/tex]
jadi jawabannya B