Matematika

Pertanyaan

:) ......Tolong yaa...... (:
:) ......Tolong yaa...... (:

1 Jawaban


  • [tex](4 - 3x)(3 - 2x) \leqslant (3x + 1)(2x - 1) \\ 12 - 8x - 9x + 6 {x}^{2} \leqslant 6 {x}^{2} - 3x + 2x - 1 \\0 \leqslant 6 {x}^{2} - 6 {x}^{2} - x + 17x - 1 - 12 \\ 0 \leqslant 16x - 13 \\ 13 \leqslant 16x \\ x \geqslant \frac{13}{16} [/tex]