Jika A+B=5AB B+C=6BC A+C=7AC.Hitung AxBxC=....?

bila a + b =5ab, b + c =7bc, c + a = 6ac, berapakah nilai a x b x c ?

Ubah ke bentuk pecahan,a + b = 5ab
(a + b)/ab = 51/a + 1/b = 5
1/b + 1/c = 7
1/c + 1/a = 6

Jumlahkan semua,
2(1/a + 1/b + 1/c) = 181/a + 1/b + 1/c = 91/c = 4
1/a = 2
1/b = 3
1/(abc) = 24abc = a x b x c = 1/24

Sukses selalu…!