nilai x yang memenuhi persamaan [tex]( \frac{1}{4} ) {}^{x - 1} = \sqrt[3]{2 } {}^{3x + 1} [/tex] adalah... sekalian caranya, makasih sebelumnya

[tex]( \frac{1}{4} ) ^{x - 1} = ( \sqrt[3]{2} ) ^{3x + 1} \\ ( {2}^{ - 1} ) ^{x - 1} = ( {2}^{ \frac{1}{3} } ) ^{3x + 1} \\ {2}^{ - x + 1} = {2}^{x + \frac{1}{3} } \\ - x + 1 = x + \frac{1}{3} \\ 2x = 1 - \frac{1}{3} \\ 2x = \frac{2}{3} \\ x = \frac{1}{3} [/tex]
semoga membantu