Diketahui besar A.panjang AB B.panjang AC

jawab
ADB siku siku sama kaki
AD= BD = 6√2
AB = √(AD²+BD²) = √144
AB = 12
<ABC = 60
<BAC= 30
<BCA = 90
BC : AC : AB = 1 :  √3 : 2

AC:  AB = √3  : 2
AC : 12 = √3 : 2
AC = 12√3 /(2)
AC = 12/2  √3
AC = 6 √3

panjang AB = 6 akar 2 x akar 2
=6 x 2 = 12 cm

panjang AC =
12 akar 3 = 2 AC
AC = 12 akar 3 : 2
= 6 akar 3