Faktor persekutuan dari 8x²-12dan 16x²-9adalah

Jawaban dibawah ini
[tex] {8x}^{2} - 12 = 0 \\ 4(2 {x}^{2} - 3) = 0 \\ x = 0 \: atau \: 2 {x}^{2} - 3 = 0 \\ {2x}^{2} = 3 \\ {x}^{2} = \frac{3}{2} \\ x = \sqrt{1.5} \\ x = 1.2[/tex]
16x^2-9=0
[tex]16x {}^{2} - 9 = 0 \\ 16 {x}^{2} = 9 \\ {x}^{2} = \frac{9}{16} \\ x = \sqrt{ \frac{9}{16} } \\ x = \frac{3}{4} [/tex]

ikuti yah moga membantu