fungsi f dinyatakan dengan rumus f(x)= ax+b. jika f(2)= 11 dan f(-5)= -10, maka nilai dari (a=b)² adalah

bismillahirrohmanirrohim
Dik :
F(x) = ax + b
F(2) = 11
F(-5) = -10
Dit :(a = b)^2
jawab
F(2) = 2a + b = 11
F(-5) = -5a + b = -10
------------------------- -
7a = 21
a= 3
2a + b= 11
2(3) + b = 11
6 + b = 11
b= 11 - 6
b= 5

=>(a = b)^2
(3 = 5)^2

MAPEL = MATEMATIKA
KELAS = 8
BAB = RELASI & FUNGSI

diketahui =
rumus fungsi ➡ f(x) = ax + b
f(2) = 11
f(-5) = -10

ditanya = ( a + b )²

f(x) = ax + b
f(2) = 2a + b = 11......( 1 )

f(x) = ax + b
f(-5) = -5a + b = -10.....( 2 )

eliminasi nilai b pada pers. ( 1 ) dan ( 2 )
2a + b = 11
-5a + b = -10
___________-
7a = 21
a = 21 ÷ 7
a = 3

subtitusi nilai a ke pers. ( 1 )
2a + b = 11
2(3) + b = 11
b = 11 - 6
b = 5

nilai ( a + b )²
= ( 3 + 5 )²
= ( 8 )²
= 64

semoga membantu