4 pangkat x+3 =⁴√16pangkat x+5 Tentukan nilai x !

[tex] {4}^{x + 3} = \sqrt[4]{ {16}^{x + 5} } \\ {4}^{x + 3} = {16}^{ \frac{x + 5}{4} } \\ {4}^{x + 3} = { ( {4}^{2} ) }^{ \frac{x + 5}{4} } \\ {4}^{x + 3} = {4 }^{ \frac{x + 5}{2} } \\x + 3 = \frac{x + 5}{2} \\ 2x + 6 = x + 5 \\ x = - 1[/tex]

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