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[tex] {25}^{2x} - {5}^{2x + 1} - 2. {5}^{2x + 3} + a = 0 \\ x1 + x2 = 2. log_{5}(2) \\ { ({5}^{2x} )}^{2} - 5. {5}^{2x} - 2. {5}^{3} . {5}^{2x} + a = 0 \\ {5}^{2x1} \times {5}^{2x2} = a \\ {5}^{2(x1 + x2)} = a \\ log_{5}(a) = 2(x1 + x2) \\ log_{5}(a) = 2.(2. log_{5}(2) ) \\ log_{5}(a) = log_{5}(16) \\ a = 16[/tex]