tolong fast guys i need your help

Mapel Math
Bab Pecahan

Ditanyakan :
Total berat ketiga barang milik pedagang tersebut

Penyelesaian :
Berat ke-3 barang
[tex] = 12 \frac{1}{2} \: kg + 5 \frac{3}{4} \: kg + 8 \frac{5}{6} \: kg \\ = \frac{25}{2 } + \frac{23}{4} + \frac{53}{6} \\ = \frac{150 + 69 + 106}{12} \\ = \frac{325}{12} = 27 \frac{1}{12} \: kg[/tex]
Pilihan C

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Mapel : Matematika
Tentang : Pecahan
Pertanyaan yg diajukan : 1
Pembahasan :

[tex]12 \frac{1}{2} = \frac{25}{2} [/tex]

[tex]5 \frac{3}{4} = \frac{23}{4} [/tex]

[tex]8 \frac{5}{6} = \frac{53}{6} [/tex]

[tex] \frac{25}{2} + \frac{23}{4} = \frac{50 + 23}{4} = \frac{73}{4} [/tex]

[tex] \frac{73}{4} + \frac{53}{6} = \frac{219 + 106}{12} = \frac{325}{12} [/tex]

[tex] \frac{325}{12} = 27 \frac{1}{12} [/tex]

Jadi, jawabannya adalah :

[tex]27 \frac{1}{12} [/tex]

Jawabanmu yg C

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✚ Heil Manstein! ✚