tolong yaaaaaaaaaaa ...

2x + 3y = 12
A(0,4)
B(6,0)

2x + y = 6
C(0,6)
D(3,0)

Titik potong
2x + 3y = 12
2x + y = 6
Kurangkan
2y = 6
y = 3
x = (6 - y)/2 = 3/2 ---> E(3/2 , 3)

titik yg memenuhi soal :
B C D E

Fungsi obyektif
f(x,y) = 6x + 2y

B(6,0) = 6.6 + 2.0 = 36
C(0,6) = 6.0 + 2.6 = 12
D(3,0) = 6.3 + 2.0 = 18
E(3/2 , 3) = 6.3/2 + 2 3 = 9 + 6 = 15

Nilai minimum saat di C = 12