tolong dibantu yaaa kakak* :))

[tex]fog(x) = \frac{2(5 - 2x) - 5}{5 - 2x + 3} = \frac{5 - 4x}{8 - 2x} \\ {fog}^{ - 1} = \\ x = \frac{5 - 4y}{8 - 2y} \\ 8x - 2xy = 5 - 4y \\ 4y - 2xy = 5 - 8x \\ y(4 - 2x) = 5 - 8x \\ y = \frac{5 - 8x}{4 - 2x} = \frac{5 - 8.( - 2)}{4 - 2.( - 2)} = \frac{21}{8} [/tex]

f(x) = (2x - 5)/(x + 3)

f^-1 (x) = (-3x - 5)/(x - 2)
f^-1 (-2) = (-3(-2) - 5)/(-2 - 2)
f^-1 (-2) = (6 - 5)/-4 = -1/4

g(x) = 5 - 2x
g^-1 (x) = (5 - x)/2

(fog)^-1 (-2)
= (g^-1 o f^-1)(-2)
= g^-1 (f^-1 (-2))
= g^-1 (-1/4)
= (5 - (-1/4))/2
= ((5×4 + 1)/4)/2
= 21/(4 . 2)
= 21/8