Matematika

Pertanyaan

Nilai dari 1/4 log 64 + 125 log 1/25 + 3^4 + 2 log 1/3 adalah

1 Jawaban

  • 1/4log64 + 125log1/25 + 3^4 + 2log1/3

    1/4log64 = (4^-1)log(4^3) = (3/(-1))4log4 = -3 x 1 = -3

    125log1/25 = (5^3)log(5^-2) = (-2/3)5log5 = (-2/3) x 1 = -2/3

    3^4 = 81

    2log1/3 = 2log(3^-1) = -1 x 2 log 3 = - 2log3

    jika semuanya di jumlah kan menghasilkan:
    (-3) + (-2/3) + 81 + (- 2log3)
    = -3 - 2/3 + 81 - 2log3
    = -11/3 + 81 - 2log3
    = (-11+243)/3 - 2log3
    = 232/3 - 2log3

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