Tolong di Jawab Ya No.4 ☺☺☺

misalkan AD = x, maka BD = 26 - x
[tex] \sqrt{ {17}^{2} - {x}^{2} } = \sqrt{ {25}^{2} - {(26 - x)}^{2} } \\ {17}^{2} - {x}^{2} = {25}^{2} - {(26 - x)}^{2} \\ {17}^{2} - {x}^{2} = {25}^{2} - ( {26}^{2} + {x}^{2} - 52x) \\ {17}^{2} + {26}^{2} - {25}^{2} = 52x \\ 289 + 51 = 52x \\ x = \frac{340}{52} = 6.5[/tex]