bantu jawab dong kak no 1 dan 2 ya kak beserta jalan nya

① x² - (m - 2)x + 4 = 0
a = 1, b = -(m - 2), c = 4

α + β = -b/a = -(-(m - 2)) = m - 2
αβ = c/a = 4

α² + β² = 8
(α + β)² - 2αβ = 8
(m - 2)² - 2(4) = 8
m² - 4m + 4 - 8 = 8
m² - 4m - 12 = 0
(m + 2)(m - 6) = 0
m = -2 atau m = 6

② y = 2x + 1, x = (y - 1)/2, kemudian masukkan ke pers. kuadrat semula diperoleh
2((x - 1)/2)² + 3((x - 1)/2) - 8 = 0
2((x² - 2x + 1)/4) + ((3x - 3)/2) - 8 = 0
((x² - 2x + 1)/2) + ((3x - 3)/2) - 8 = 0
x² - 2x + 1 + 3x - 3 - 16 = 0
x² + x - 18 = 0

semoga membantu ^^