tolong dijawab siang mau dikumpul

Diketahui : mA = 6kg, mB = 3 kg,  μ = 1/3
                 
Ditanya: tegangan tali T?

Jawab:
Fg = N.μ = 60.1/3 = 20 N

[tex] \alpha = \frac{W1-Fg}{m1+m2} \\ \\ \frac{30-20}{3+6} =\frac{10}{9} m/s^2[/tex]

ΣF=mA.α
T-Fg=6.10/9
T-20=7
T=7+20 = 27 N