Matematika

Pertanyaan

Tent. Rumus Fog dan gof @ f(x)=x²-3 , g(x)=x³

1 Jawaban

  • fog(x) = f(g(x))
    =f(x³)
    = (x³) ² - 3
    = x^6 — 3

    gof(x) = g(f(x))
    = g (x²-3)
    = (x²) ³ - 3
    = x^6 — 3

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