No 3 gmna ya tolong kasih jawabannya

[tex]a.x = \sqrt{ {20}^{2} - {12}^{2} } \\ x = \sqrt{400 - 144} \\ x = \sqrt{256} \\ x = 16cm \\ b.tinggi \: segitiga \: kecil = \sqrt{ {13}^{2} - {5}^{2} } \\ = \sqrt{169 - 25} \\ = \sqrt{144} \\ = 12mm \\ x = \sqrt{ {35}^{2} + {12}^{2} } \\ x = \sqrt{1225 + 144} \\ x = \sqrt{1369} \\ x = 37mm[/tex]