(akar 3 + akar 7)(akar 3 - akar 7)/2 akar 5 - 4 akar 2 Tolong dibantu yah
Matematika
Nadyat12
Pertanyaan
(akar 3 + akar 7)(akar 3 - akar 7)/2 akar 5 - 4 akar 2
Tolong dibantu yah
Tolong dibantu yah
1 Jawaban
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1. Jawaban masbro18
[tex] \frac{ (\sqrt{3} + \sqrt{7})( \sqrt{3} - \sqrt{7} )}{2 \sqrt{5} - 4 \sqrt{2} } \\ = \frac{ \sqrt{9} - \sqrt{21} + \sqrt{21} - \sqrt{49} }{2 \sqrt{5} - 4 \sqrt{2} } \\ = \frac{3 - 7}{2 \sqrt{5} - 4 \sqrt{2}} \\ = \frac{ - 4}{ 2\sqrt{5} - 4 \sqrt{2} } \times \frac{2 \sqrt{5} + 4 \sqrt{2} }{2 \sqrt{5} + 4 \sqrt{2} } \\ = \frac{ - 4(2 \sqrt{5} + 4 \sqrt{2} )}{4 \sqrt{25} + 8 \sqrt{10} - 8 \sqrt{10} - 16 \sqrt{4} } \\ = \frac{ - 8 \sqrt{5} - 16 \sqrt{2} }{4(5) - 16(2)} \\ = \frac{ - 8 \sqrt{5} - 16 \sqrt{2} }{20 - 32} \\ = \frac{ - 8 \sqrt{5} - 16 \sqrt{2} }{ - 12} \\ = \frac{ - 4(2 \sqrt{5 } + 4 \sqrt{2} )}{ - 4(3)} \\ = \frac{2 \sqrt{5} + 4 \sqrt{2} }{3} [/tex]
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