please help me .........

jawab

1.
lim(x->∞) (2 - 6x)^3/ (4x+1)^3
(bagi kooef pangkay tertinggi) 
x--> ∞ =  (-6/4)^3 = (-3/2)^3 =  -27 /8

2.
f'(x) = [ (2x+4)(2x-1) - 2(x^2 + 4x)] (2x -1)^2
f'(2) --> x = 2

f' (2) = [ (12)(3) - 2(12}/[3)^2 = (36 -24)/ (27)
f' (2) =  12/27 = 4/9