Jika f(x) =5x+2 dan g(x) =x+3/3x-1 komposisi fungsi (f 0 g) (x) =

(fog)(x)
= 5(x + 3)/(3x - 1) + 2
= (5(x + 3) + 2(3x - 1)) / (3x - 1)
= (5x + 15 + 6x - 2) / (3x - 1)
= (11x + 13) / (3x - 1)

[tex](fog)(x) = > (f(g(x)) = f(x)[/tex]
[tex](f( \frac{x + 3}{3x - 1} ) = 5x + 2 = > 5( \frac{x + 3}{3x - 1} ) + 2 = > \frac{5x + 15}{15x - 5} + 2 = > \frac{x + 3}{3x - 1} + 2 = > [/tex]