Jika f(x) =5x+2 dan g(x) =x+3/3x-1 komposisi fungsi (f 0 g) (x) =

f(g(x)) = 5(x+3/3x-1)+2 =( 5x+15/3x-1)+2
= (5x+15+6x-2)/3x-1
= 11x+13/3x-1

[tex]f(x) = 5x + 2 \\ g(x) = \frac{x + 3}{3x - 1} \\ fog(x) = f(g(x)) \\ fog(x) = f( \frac{x + 3}{3x - 1} ) \\ fog(x) = 5( \frac{x + 3}{3x - 1} ) + 2 \\ fog(x) = \frac{5x + 15}{3x - 1} + 2 \\ fog(x) = \frac{5x + 15}{3x - 1} + 2( \frac{3x - 1}{3x - 1} ) \\ fog(x) = \frac{5x + 15}{3x - 1} + \frac{6x - 2}{3x - 1} \\ fog(x) = \frac{5x + 15 + 6x - 2}{3x - 1} \\ fog(x) = \frac{11x + 13}{3x - 1} [/tex]
Semoga dapat dipahami