Matematika

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(3√5+4√2)²=



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  • [tex] ({3 \sqrt{5} + 4 \sqrt{2} })^{2} \\ = ({3 \sqrt{5} + 4 \sqrt{2} }) \times ({3 \sqrt{5} + 4 \sqrt{2} }) \\ = 9.5 + 12 \sqrt{10} + 12 \sqrt{10} + 16.2 \\ = 45 + 24 \sqrt{10} + 32 \\ = 77 + 24 \sqrt{10} [/tex]

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