Tentukan limit fungsi dari 1. Lim X-3 x->3 X²+X-12 2.lim X²-16 x->3 X -4 3.lim X²+2X x->2 X-1

jawab

1.
= lim(x->3) ( x-3)/ (x -3)(x + 4)
= lim(x->3) 1/(x+4)
x= 3 --> limit = 1/7

2.
= lim(x->4) (x² -16)/( x- 4)
= lim(x->4) (x -4)(x + 4)/ (x- 4)
= lim(x->4) x + 4
x = 4 --> limit= 4 + 4 = 8

3.
= lim x -> 2)  (x²+x )/(x-1)
x= 2 , limit = (2²+2)/(2-1) = 6