1.√27+√8-√48= tolong kerjakan yang bener ...akan saya jadikan jawaban terbrainly.

Mapel : Matematika
Bab : Akar

[tex] \sqrt{27} + \sqrt{8} - \sqrt{48} [/tex]
[tex] = \sqrt{9 \times 3} + \sqrt{4 \times 2} - \sqrt{16 \times 3} [/tex]
[tex] = 3 \sqrt{3} + 2 \sqrt{2} - 4 \sqrt{3} [/tex]

[tex] = 2 \sqrt{2} - \sqrt{3} [/tex]

√27 + √8 - √48 =
√(9x3) + √(4x2) - √(16x3) =
3√3 + 2√2 - 4√3 =
2√2 - √3


GoodLuck :D