Hitunglah 2√32 - 3√8/9 - √1/8= Tolong jawab dongg

[tex]2 \sqrt{32}-3 \sqrt{ \frac{8}{9} } - \sqrt{ \frac{1}{8} } \\ = 2 \sqrt{16\times2}-3 \sqrt{ \frac{4\times2}{9} } - \sqrt{ \frac{2}{16} } \\ = 2 \times 4 \sqrt{2}-3 \times \frac{2}{3} \sqrt{2} - \frac{1}{4} \sqrt{2} \\ = 8 \sqrt{2} - 2 \sqrt{2} - \frac{1}{4} \sqrt{2} \\ = (8-2-\frac{1}{4} ) \sqrt{2} \\ =( \frac{32-8-1}{4} )\sqrt{2} \\ = \frac{23}{4} \sqrt{2}\\[/tex]