Kimia

Pertanyaan

hitung ph larutan 250 mllarutan, Naoh 0,001 mol

1 Jawaban

  • n NaOH = 10^-³ mol
    V NaOH = 0,25 L

    [OH] = n NaOH/V NaOH
    [OH] = 0,001 / 0,25
    [OH] = 0,004 = 4×10^-3
    pOH = 3 - log4
    pH = 14 - (3-log4)
    pH = 11 + log4

Pertanyaan Lainnya