Limit x->4 akar x2+9 =

Bab : Limit

Penyelesaian:
Lim x --> 4     √(x² + 9)
= √(4² + 9)
= √(16 + 9)
= √25
= 5

[tex]lim \: \sqrt{ {x}^{2} + 9 } \\ x - > 4 \\ = \sqrt{ {4}^{2} + 9} \\ = \sqrt{25} [/tex]
=+-5
+5 atau -5